a_n = a + (n-1) \cdot d = 3 + (n-1) \cdot 5
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- m = 5
- $$Question: How many numbers are in the list \( 3, 8, 13, \ldots, 98 \)?
- Solution: The given sequence is an arithmetic sequence with the first term \( a = 3 \) and common difference \( d = 5 \). The general term of the sequence is given by:
- We need to find \( n \) such that \( a_n = 98 \):
- + (n-1) \cdot 5 = 98
- Subtract 3 from both sides:
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